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255x^2-82.6x+6.484905=0
a = 255; b = -82.6; c = +6.484905;
Δ = b2-4ac
Δ = -82.62-4·255·6.484905
Δ = 208.1569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-82.6)-\sqrt{208.1569}}{2*255}=\frac{82.6-\sqrt{208.1569}}{510} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-82.6)+\sqrt{208.1569}}{2*255}=\frac{82.6+\sqrt{208.1569}}{510} $
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